Displaying Data from Database as Table PHP mysqli fetch array

Displaying Data from Database Using PHP MySQLi

Displaying Data from Database as Table PHP mysqli fetch array

Hi Guys in This Tutorial we will Learn how to Display Data from MySQL Database using PHP MySQLi.

Database Structure:

Database name: tutorial
Table Name: test
SQL code for table test Creation:

CREATE TABLE IF NOT EXISTS `test` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `name` varchar(150) NOT NULL,
  `email` varchar(150) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=5 DEFAULT CHARSET=latin1;

Dumping Data for Table test

INSERT INTO `test` (`id`, `name`, `email`) VALUES
(12, 'ANJANBD', 'Anjankumardhali6@gmail.com'),
(11, 'Krishna', 'krishna@mail.com'),
(3, 'Rupam Mondal', 'RupomMondal@gmail.com'),
(4, 'ANJAN', 'KumarANjan@gmail.com'),
(5, 'Biswas Shiuli', 'ShiuliBiswas@gmail.com'),
(7, 'Hrithik', 'Hrithik@gmail.com'),
(8, 'Modhu Bonik', 'Modhu360@gmail.com'),
(9, 'Rupam Mondal Joy', 'RupomMondal@gmail.com'),
(13, 'Rupa', 'Rupa@hotmail.com'),
(14, 'ANJAN', 'Kumar@gmail.com'),
(15, 'ANJANBD', 'Anjankumardhali6@gmail.com'),
(16, 'Krishna', 'krishna@mail.com'),
(17, 'Rupam Mondal', 'RupomMondal@gmail.com'),
(18, 'ANJAN', 'KumarANjan@gmail.com'),
(19, 'Biswas Shiuli', 'ShiuliBiswas@gmail.com'),
(20, 'Hrithik', 'Hrithik@gmail.com'),
(21, 'Modhu Bonik', 'Modhu360@gmail.com'),
(22, 'Rupam Mondal Joy', 'RupomMondal@gmail.com'),
(23, 'Rupa', 'Rupa@hotmail.com'),
(24, 'ANJAN', 'Kumar@gmail.com'),
(25, 'ANJANBD', 'Anjankumardhali6@gmail.com'),
(26, 'ANJANBD60', 'Anjankumardhali6@gmail.comss'),
(27, 'Priyoshi', 'Priyoshi@gmail.com'),
(28, 'Rupom Chakma', 'Rupam@gmail.com'),
(29, 'Monisha Roy', 'Monisharoy@gmail.com');

Directory or Folder and files Structure:

Create 3 files in any directory under htdocs folder.
1.connect.php
 2.index.php [Displaying Data]
 3.style.css

Displaying Data from Database as Table PHP mysqli fetch array

Codes for Connect.php

<?php
$host = "localhost"; //Host name
$username = "root";  //MySQL Username .'root' is default
$password = "";  //MySQL Password
$db_name="tutorial"; //Database Name

// Create connection passing host,username,password and db_name 
$conn = new mysqli($host, $username, $password,$db_name);

// Checking connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}
?>

Codes for index.php

<link rel="stylesheet" href="style.css" type="text/css"/>
<?php
include("connect.php");;
$sql = "SELECT id,name, email FROM test ORDER by id ASC ";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
    echo "<table>";
 echo "<tr>";
 echo "<th>ID</th>";
 echo "<th>Name</th>";
 echo "<th>Email</th>";
 echo "</tr>";
    // output data of each row
    while($row = $result->fetch_assoc()) {
     echo "<tr>";
      echo "<td>$row[id]</td>";
   echo "<td>$row[name]</td>";
   echo "<td>$row[email]</td>";
   echo "</tr>";
    }
    echo "</table>";
} else {
    echo "0 results";
}
$conn->close();
?>

Codes for style.css

table th, td{
   border: 1px solid green;
   text-align:left;
}
th,td{
 padding:8px;
 
}
table{
 border-collapse:collapse;
 width:50%;
}
th{
 padding:15px;
 background:lightgreen;
 font-size:20px;
 font-weight:bold;
}
tr:nth-child(odd){background:#808080}
  }
 

If you Like This article Please Like and Share With Your Friends.
Keep Visiting for More Codes.Thank you.